Swisscom tv 2 box problem algebra

In the above diagram, the yellow portion of the box is the bottom and the blue portions are the sides.

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However, if you do pay the Anschluss fee, Cablecom may still sell you a modem with 0chf monthly charges. The x-intercepts or the values of x that produce a volume of in.

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We have investigated this problem using several distinct methods with each method given us a better understanding of the problem. The following Algebra Expressor graph supports this finding.

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In this diagram and the one below, the volume approaches zero, but the x values are very different. From this table, you notice that the other x-value that produces a volume of cu.

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We do this by using the following spreadsheet. Let's first find the x values that produce a volume of cu. We will use the following volume formula to find this x-value. Now, we need to find the other x-value that produces a volume of in. What size square would produce the maximum volume? You can see this same pattern for any desired volume, except for the maximum volume. First, we are going to found out what x should be in order to have a volume of cu. Now let's use our spreadsheet and explore these roots more closely. If a small square of the same size is cut from each corner and each side folded up along the cuts to form a lidless box, what is the maximum volume of the box? We also notice that there are two x values that produce a volume of cu. We have investigated this problem using several distinct methods with each method given us a better understanding of the problem. Basically a freebie to stop you closing off the Anschluss, as they still make money that way. This diagram does not have the dimensions that our real box has i. From our work in Algebra Expresser, we know that the zero is somewhere between 1.

To do this, we need to take the first derivative of our volume function.

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The Box Problem: Algebra 2 Resources